The speaker discusses how to solve a problem with ADM by organizing activities in a network, starting with the B and C activities and connecting the nodes. They explain how to adjust properties of certain lines and calculate dates. The speaker emphasizes the importance of finishing certain activities for optimal results and explains the use of certain nodes for critical activities.
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I Hello again. Today we're going to start trying to solve the

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problem with ADM to see how can we draw the network, and how can we

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perform the calculations of error Diagramming Method. What we have

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here in front of us is a table showing different activities in

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the form of ij, together with the IPAS and the durations for each

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activities, for each one of the activities. So what we're going to

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do is, first, we're going to try to draw this network. Here we have

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an Excel file. We're going to try to draw the the network in Excel.

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And that's basically a very simple task. What we're going to do is

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we're going to go to insert

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and shapes. We're going to select a an oval, which we're going to

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make, like a circle here,

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and then what we're going to do, basically, is just copy and paste

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this circle several times,

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and now we're going to start dragging these circles one by one

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and drawing the network. So we start with activity AB, of course,

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as we notice here, we have ab, ac and ad. All of these three

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activities have no immediate predecessors. So

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we notice that these three activities have no immediate

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predecessors, which means that they start the network. So we're

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So we're going to drag one of these circles here, and that's

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going to be the node A. You can type a inside like that,

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and then we're gonna add drag another node here,

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B, another node

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C and another node D.

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So here we have

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B,

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C

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and D.

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What we're going to do next is we're going to connect these with

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a line. So we're going to select shapes. We can select an arrow, as

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we mentioned before, an arrow or a line doesn't make much difference,

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since we know that the flow is going to be from left to right, so

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we're going to connect AB,

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we're going To connect

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AC,

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and we're going to connect ad.

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So here we're done with the first three activities. Next we're going

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to look from B we have activity B, C and B, E, and both of them have

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a B as predecessor. So we're gonna drag two nodes here. So

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and connect,

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and here we have

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BC.

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Well, actually, BC is already here, so we don't need to drag a

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couple of nodes. We can just connect BC like that.

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And that's going to be be,

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but notice something here,

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activity BC has zero duration,

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therefore it has to be a dummy activity. So what we're going to

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do, we're going to change the properties of this line,

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going to format shape by right clicking on the line and changing

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it into a dash type, something like that.

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And here we have it on the activity between B and C, B and C.

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So then we have CF, which follows AC and BC

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CF. So let's just drag this node here,

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and this is going to be f,

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and draw the line CF and

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okay,

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and then we have CG, also has predecessors of AC and BC, so we

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have g is.

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Going to be somewhere here. So let's drag another node G,

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and the activity

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connecting the two nodes. Remember, in ATM, the activity is

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represented by the arrow connecting the two nodes,

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and then we have also DG, which has as a predecessor, ad. So we're

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going to connect DG,

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so it's very convenient that we place G at this position. Now you

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can you're going to see that we're going to have some different

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attempts at arranging these activities in the proper layout to

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be legible as much as possible. So far, it's working fine,

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alright. So next we have activity EI

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and EF, and both of them have, as predecessors, be so EI and EF,

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dragging two nodes, actually one node only, because here we have F

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already existing. So we're going to connect EI. This is going to be

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I

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connect Ei,

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and also connect EF. We're

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both of them have duration. So we only, as you notice from this

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table, we only have one dummy activity, which is activity, BC,

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all right, so now the next one is going to be G, H, which has as

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predecessors, CG and DG. So we're going to have H somewhere here,

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and we're going to connect

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GH.

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Next we have f j, F j, which has as predecessors, E, F and C, F. So

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let's put J somewhere here

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and connect

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F j, so

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and then we also have HJ and ij. We already have the node, so all

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we have to do is connect i

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i,

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and here we have our network.

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We have all the activities,

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i, j

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as its predecessor, e, i, that's fine. And HJ has its predecessor,

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GH, that's perfectly fine. So we ended up with one extra node. We

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can just delete that

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very well. The next step is to calculate the dates. As you

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zero, so we're going to put zero here, and zero, also here and zero

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also here.

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Let's just make some adjustments so that it appears in a nicer way.

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And here we're going to make it like that.

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Actually, you can try to Okay, so far so good.

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And then activity AB has a duration of four days, so we're

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gonna finish on day four.

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So also, let's make it left adjusted.

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Activity AC has a duration of nine days,

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so it's going to finish on day nine.

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Ad has a duration of 16 days, so it's going to finish on day 16. I

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now activity, the node B has the date number four, so anything that

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starts from B is going to be on four. So we're going to put four

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here

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and four here as well.

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Now activity be has a duration of 13 days, so it's going to end on

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day 17. So.

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The Activity BC is a dummy activity, so the duration is four,

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therefore it's going to end on day four as well.

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Centered.

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Now at node C, we have two dates coming we have four coming from

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BC, and we have nine coming from AC. As you remember from our

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lecture, we're going to take the larger number in the forward pass,

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so we're going to put here nine

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and nine.

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Duration of CG is 14 days, so it's going to end on day 23

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and duration of CF is seven days, so it's going to end on day 16.

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Duration of d G is

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eight days. It's going to start on day 16,

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and it's going to end on day 24 I

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now at node G again, we have two numbers. We have 23 and 24

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therefore the number that's going to proceed with us is going to be

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the 24 the larger number.

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GH has a duration of 12 days, so it's going to end on day 36

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and

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as you can see, it's very simple calculations. We can just you can

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just finish the calculations for this network. Let's just finish

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the forward pass, and you can go ahead and do the backward pass

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yourself.

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and EI

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is 16 days. So it's going to be 33

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here. Also we have 17

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and EF has a duration of nine days. So it's going to be 26

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so at node F, we have 16 and 26 we're going to take the 26

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and F, J has a duration of 10 days. So here we're going to have

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36

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and then I we have here 33

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and duration of ij is 13, so it's going to be

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46 40 6h.

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J is going to start here on 36

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and has a duration of 11 days. So it's going to be 47

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now we have three numbers going to know, j we have 4636 and 47 the

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largest number, of course, is 47 so that's going to be my end of

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the project. The project started on day zero and ended on day 47

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as you can see, the calculations are not that hard at all. They are

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very straightforward and simple. What we're going to do in the

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backward pass, actually, is reverse everything that we did in

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the forward pass. Let me start the backward pass and leave it for you

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to finish. So let's start with the first set of activities. Here,

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we're going to start with 47 as the late start, which is going to

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be underneath the arrow 47 and let's change the color of these to

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be red, for example,

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just to distinguish the forward from the backward passes. So 47

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the duration of HJ was

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11 days. So it's going to be 36

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now we're subtracting. Remember, I.

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Now you notice here that HJ has 4747 3636 so obviously this is

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going to be a critical activity. Right now, if you follow that,

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you're going to find that the critical path is going to be

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basically that bottom path,

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because this is going to be the longest path, leading with giving

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us the longest dates, the latest dates. So it's going to be a, d,

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g, h j, that's going to be our critical path at the end. How did

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I know that? Because it has to be a continuous path. And since it

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passes through h j, then it has to be that one. Why didn't we say a C

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and C G? Because again, the number coming to G from D, which is 24 is

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larger than the number coming from C, which is 23 therefore the

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critical activity is going to be DG. But let's go ahead and do a

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couple more activities with the dates. So here we're going to

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let's put

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it here,

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red 47 minus 10, that's going to be 37

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now notice this activity has how many days of total float 47 minus

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36 or 37 minus 26 which is 11 days of total float going to activity,

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i j, it's going to be again 47

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minus.

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This is i j

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minus 13, so it's going to be 34

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and you can just keep doing the backward pass. This one is going

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to have only one day of total float. What we can also do at the

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end, we can just change the color of the nodes that are going to be

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critical.

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So we're going to make it something like this,

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just to show them in a different color, so that they have a special

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status as critical activities.

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And we can also change the color of these lines. We're going to

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select this group of lines, 1234,

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activities, and right click Format objects. Change the color line

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color. Let's make it red as critical

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and here's our critical path. That was really simple, wasn't it? So

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what you have to do is finish that as a as a practice, try to finish

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this network and see if you're going to get the same numbers for

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activities, GH, Bg and A, D, which should be critical, and then

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calculate the total float for the other activities. That's basically

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our exercise for today. So.

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